25=4x^2/3

Solution for 25=4x^2/3 equation:

25=4x^2/3

We move all terms to the left:

25-(4x^2/3)=0

We get rid of parentheses

-4x^2/3+25=0

We multiply all the terms by the denominator


-4x^2+25*3=0

We add all the numbers together, and all the variables

-4x^2+75=0

a = -4; b = 0; c = +75;
Δ = b2-4ac
Δ = 02-4·(-4)·75
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{3}}{2*-4}=\frac{0-20\sqrt{3}}{-8}
=-\frac{20\sqrt{3}}{-8}
=-\frac{5\sqrt{3}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{3}}{2*-4}=\frac{0+20\sqrt{3}}{-8}
=\frac{20\sqrt{3}}{-8}
=\frac{5\sqrt{3}}{-2}
$